Bifalgorithm post · Computer science one · Computing a Logarithm
Why can an extra semicolon make an if statement behave incorrectly?
Why can an extra semicolon make an if statement behave incorrectly? (Computer science one · Computing a Logarithm) — "Some compilers may give a warning, but th…
Ideas in this flowchart
- A semicolon can make an if statement control an empty statement instead of the following print block.
- The code is valid Java; a compiler may issue a warning, but it compiles and runs.
- An if statement binds to the immediately following executable statement or code block.
- The semicolon supplies an empty executable statement for the if statement.
- The code is effectively equivalent to: int x = 15; if(x < 10) { } System.out.println("x is less than 10");
- The print block follows the empty statement but is not bound to the if statement.
- Therefore, the print statement executes regardless of the value of x.
- With x = 15, the program still prints "x is less than 10," contrary to the intended behavior.
