Bifalgorithm post

Remember the duration of various waves segments and intervals in the ECC EC paper will move in such a manner. In 60 seconds, 300 big boxes will be covered. So for each big box it will take 60 by 300 is equal to 0.2 settings. And each big box can contain five small boxes and for each small box can you take zero 0.2 by five is equal to ZE 0.04 seconds. Here remember the of 2 one. That means P wave will take 200 small boxes that is zero 0.1 second PR segment will take 2 one small boxes. Zero 0.1 second small box will take 200 small boxes, that is ZE 0.1 second SD separate plus T wave together will take seven and half small boxes that is zero 0.1. 2 three equal to 0.3 seconds. Let's say the duration of in PR in interval is equal to P wave plus PR segment is equal to zero 0.2 settings. Q p is equal to Q complex plus SD segment plus e is equal to 0.1 +3 is equal to zero 0.4 seconds.

Remember the duration of various waves segments and intervals in the ECC EC paper will move in such a manner. In 60 seconds, 300 big boxes will be covered. So…